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A nice little idempotent function -- calling it two, three, n times has exactly the same result as calling it once.

The place you see the other characterization of idempotence all the time is in C++ header files. Include a needed header zero times and you'll get "not defined" errors. Accidentally include it twice and you'll get "redefinition" errors. It's a major pain to make sure that every header file is included exactly once. Therefore, most headers use some trick to make them idempotent under the inclusion operation:

#ifndef STUFF_H_INCLUDED#define STUFF_H_INCLUDED

//headers here

#endif // STUFF_H_INCLUDED

or in more modern systems, the #pragma once directive makes headers idempotent under inclusion.

Good stuff… I approve.

Funny stuff. After doing some DBA style work a few months ago, I wrote a little on idempotence myself. I like the technique a great deal.

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Just to be annoyingly picky, "subtraction" is a function that takes two values, so I’m not sure what it means to say that no value is idempotent under subtraction. Unless the function is x -= 1, I suppose

Stuart Langridge wrote: Just to be annoyingly picky, "subtraction" is a function that takes two values, so I’m not sure what it means to say that no value is idempotent under subtraction. Unless the function is x -= 1, I suppose

I am one of those programmers with a mathematical background Eric is talking about, so I can be really picky, if I want to: the function "x -= 1" is idempotent for the value -inf, and probably for some NaNs, too.

I indended to say "subtracting a non-zero value" — I’ve fixed the text.

I’m no a C programmer, but it looks like GetTypeLibCreator is not an idempotent function, because its input and output types are not the same, i.e. you cannot do GetTypeLibCreator(GetTypeLibCreator(x))

More importantly, wouldn’t it be considered non-idempotent because of the AddRef call which changes the reference count on the returned object. Calling this function twice would not result in the same system state as calling it once…

If a function is idempotent, does that mean it’s really a dysfunction?

Oops, missed a couple letters there…

Quote: The operation "subtracting any non-zero value" has no idempotent values

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